The ascending order of \(\sqrt{2}, \sqrt[3]{4}\) and \(\sqrt[4]{6}\) is -

1

\(\sqrt{2}, \sqrt[3]{4}, \sqrt[4]{6}\)

2

\(\sqrt[4]{6}, \sqrt[3]{4}, \sqrt{2}\)

3

\(\sqrt[4]{6}, \sqrt{2}, \sqrt[3]{4}\)

4

\(\sqrt{2}, \sqrt[4]{6}, \sqrt[3]{4}\)

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