The specific weight of a liquid having a volume of 6 m3 and weight 42 kN is:

1
7 m3/kN
2
7 kN/m3
3
\(​\frac{1}{7}\) m3/kN
4
\(​\frac{1}{7}\) kN/m3

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation