sin A + cos B = x and cos A + sin B = y then the value of sin A cos B + cos A sin B -

1
x2 + y2 - 2
2
x2 + y2 + 2
3
\(\frac{{{x^2} + {y^2} - 2}}{2}\)
4
\(\frac{{{x^2} + {y^2} + 2}}{2}\)

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