If modular ratio is ‘m’ effective depth is D and stress ratio if ‘r’ \(\left( {r = \frac{{{\sigma _{st}}}}{{{\sigma _{cbc}}}}} \right)\) the depth of neutral axis of a balanced section is
1
\(\left( {\frac{m}{{m - r}}} \right) \times D\)
2
\(\left( {\frac{m}{{m + r}}} \right)D\)
3
\(\left( {\frac{{m + r}}{m}} \right) \times D\)
4
\(\frac{m}{r} \times D\)