A tank of uniform cross sectional cross area (A) containing liquid upto height (H) has an orifice of cross sectional areas (a) at its bottom. The time required to empty the tank completely will be
1
\(\frac{{2A\sqrt {{H_1}} }}{{{C_d}a\sqrt {2g} }}\)
2
\(\frac{{2A{H_1}}}{{{C_d}a\sqrt {2g} }}\)
3
\(\frac{{2AH_1^{3/2}}}{{{C_d}a\sqrt {2g} }}\)
4
\(\frac{{2AH_1^2}}{{{C_d}a\sqrt {2g} }}\)