The voltage V0 for the circuit shown in the given figure will be

1
\({V_s}\left( {1 + \frac{M}{{{L_1}}}} \right)\)
2
\({V_s}\left( {1 - \frac{M}{{{L_1}}}} \right)\)
3
\({V_s}\left( {\frac{M}{{{L_1}}} - 1} \right)\)
4
\({V_s}\left( {1 - \frac{M}{{{L_2}}}} \right)\)

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