A region shown below contains a perfect conducting half-space and air. The surface current \(\overrightarrow {{K_S}} \) on the surface of the perfect conductor is \(\overrightarrow {{K_S}} = \hat x2\) amperes per meter. The tangential \(\vec H_t\) field in the air just above the perfect conductor is

1
(x̂ + ẑ) 2 amperes per meter
2
x̂ 2 amperes per meter
3
–ẑ 2 amperes per meter
4
ẑ 2 amperes per meter

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