Find the sum to n terms of the series:

0.5 + 0.55 + 0.555 + 0.5555 + -----------

1
1/162 × [10(10-n – 1) – 9n]
2
1/90 × [10(10n – 1) – 9n]
3
5/90 × [10(10n – 1) + 9n]
4
5/81 × [10(10-n – 1) + 9n]

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