If 'Pm' is the gross mechanical power developed, 'Pcu' is the rotor copper loss and 's' is the slip of induction motor, then the ratio of rotor copper loss to the gross mechanical power developed is _____.

1
\(\frac{{{P_{Cu}}}}{{{P_m}}} = \frac{s}{{1 - s}}\)
2
\(\frac{{{P_{Cu}}}}{{{P_m}}} = \frac{{1 - s}}{s}\)
3
\(\frac{{{P_{Cu}}}}{{{P_m}}} = 1 - s\)
4
\(\frac{{{P_{Cu}}}}{{{P_m}}} = s\)
5
\(\frac{{{P_{Cu}}}}{{{P_m}}} = \frac{{1}}{s}\)

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