Gauss law relate the electric field intensity \(\overrightarrow{E}\) with the volume charge density 'ρ' at a point as -
1
\(\bigtriangledown \times \overrightarrow{E} = \varepsilon_0\rho\)
2
\(\bigtriangledown \times \overrightarrow{E} = \frac{\rho}{\epsilon_0}\)
3
\(\bigtriangledown . \overrightarrow{E} = \epsilon_0\rho\)
4
\(\bigtriangledown . \overrightarrow{E} = \frac{\rho}{\epsilon_0}\)