For the given transfer function:

\(G\left( s \right) = \frac{{Y\left( s \right)}}{{R\left( s \right)}} = \frac{1}{{{s^2} + 3s + 2}}\)

the response y(t) for a step input r(t) = 5u(t) will be

1
\(\left[ {\frac{5}{2} - 5{e^{ - t}} + \frac{5}{2}{e^{ - 2t}}} \right]u\left( t \right)\)
2
\(\left[ {\frac{5}{2} - 5{e^{ - t}}} \right]u\left( t \right)\)
3
\(\left[ {\frac{5}{2} + \frac{5}{2}{e^{ - 2t}}} \right]u\left( t \right)\)
4
\(\left[ { - 5{e^{ - t}} + \frac{5}{2}{e^{ - 2t}}} \right]u\left( t \right)\)

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