The solution of the differential equation \(\frac{{{d^2}y}}{{d{x^2}}} - 3\frac{{dy}}{{dx}} + 2y = {e^x},\;y = 3\) and \(\frac{{dy}}{{dx}} = 3\), when x = 0 is

1
y = 2ex + e2x - xex
2
y = ex – e2x + xex
3
y = 2ex + e-2x – xe-x
4
y = ex + 2e2x – x2ex

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