The Bode plot shown in figure has open loop transfer function equal to

1
\(\frac{{1585{{\rm{s}}^2}}}{{\left( {{\rm{s}} + 1} \right)\left( {{\rm{s}} + 5} \right)\left( {{\rm{s}} + 10} \right)}}\)
2
\(\frac{{1585{\rm{\;}}\left( {{\rm{s}} + 1} \right)}}{{{{\rm{s}}^2}\left( {{\rm{s}} + 5} \right)\left( {{\rm{s}} + 10} \right)}}\)
3
\(\frac{{1585{{\rm{s}}^2}}}{{\left( {1 + {\rm{s}}} \right)\left( {1 + 0.2{\rm{s}}} \right)\left( {1 + 0.1{\rm{s}}} \right)}}\)
4
\(\frac{{1585{\rm{\;}}\left( {{\rm{s}} + 1} \right)}}{{{{\rm{s}}^2}\left( {1 + 0.2{\rm{s}}} \right)\left( {1 + 0.1{\rm{s}}} \right)}}{\rm{\;}}\)

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