If \(\tan \theta = \dfrac{4}{3} \ \rm then \ \left(\dfrac{2 \sin \theta - 3 \cos \theta}{2 \sin \theta + 3 \cos \theta }\right)=?\)

1
0
2
-1
3
\(-\dfrac{1}{7}\)
4
\(-\dfrac{1}{17}\)

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