A signal m(t) with bandwidth 500 Hz is first multiplied by a signal g(t) where \(g\left( t \right) = \mathop \sum \limits_{k = \infty }^\infty {\left( { - 1} \right)^k}\delta \left( {t - 0.5 \times {{10}^{ - 4}}k} \right)\)

The resulting signal is then passed through an ideal low pass filter with bandwidth 1 kHz. The output of the low pass filter would be

1
δ(t
2
m(t)
3
0
4
m(t) δ(t)

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