If the area of a circle increases at the rate of \(\frac{1}{\sqrt{\pi}}\) sq. units/sec, then the rate (in units/sec) at which the perimeter of the circle changes, when perimeter is \(\sqrt{\pi}\) units, is

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2
2
4
3
\(\frac{1}{\sqrt{\pi}}\)
4
\(\sqrt{\pi}\)

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