The driving and driven shafts connected by a Hooke’s joint are inclined by an angle α to each other. The angle through which the driving shaft turns is given by θ. The condition for the two shafts to have equal speeds is
1
cosθ = sinα
2
\(\sin {\rm{\theta }} = \pm \sqrt {\tan {\rm{\alpha }}} \)
3
\(\tan {\rm{\theta }} = \pm \sqrt {\cos {\rm{\alpha }}} \)
4
cot θ = cos α