For two events A, B
P(A ∪ B) = \(\frac{7}{12}\), P(A) = \(\frac{5}{12}\), P(B) = \(\frac{3}{12}\) Then P(A ∩ B) =
1
\(\frac{1}{2}\)
2
\(\frac{1}{12}\)
3
\(\frac{1}{6}\)
4
\(\frac{1}{3}\)
For two events A, B
P(A ∪ B) = \(\frac{7}{12}\), P(A) = \(\frac{5}{12}\), P(B) = \(\frac{3}{12}\) Then P(A ∩ B) =