Let \(\rm \int \frac{2-tan x}{3+tan x}dx=\frac{1}{2}\left(\alpha x+log_e\mid\beta sin x+\gamma cos x\mid\right)+C\,\), where C is the constant of integration.
Then \(\rm \alpha+\frac{\gamma}{\beta}\) is equal to :
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Let \(\rm \int \frac{2-tan x}{3+tan x}dx=\frac{1}{2}\left(\alpha x+log_e\mid\beta sin x+\gamma cos x\mid\right)+C\,\), where C is the constant of integration.
Then \(\rm \alpha+\frac{\gamma}{\beta}\) is equal to :