The Laplace transform of a signal f(t) is given as:
\(F\left( s \right)=\frac{5s+3}{s\left( s+1 \right)}.\)
The signal will be:
1
2u(t) + 3e-t
2
3u(t) – 2e-t
3
3u(t) + 2e-t
4
2u(t) – 3e-t
The Laplace transform of a signal f(t) is given as:
\(F\left( s \right)=\frac{5s+3}{s\left( s+1 \right)}.\)
The signal will be: