engineering recuitment JSSC JE Mock Test 2023 Thermodynamics First Law of Thermodynamics Steady Flow Energy Equation
In a steady flow system, a substance flows at a rate of 5 kg/s.
The following data is given for the entry and exit of the system.
At entry: Pressure = 600 kPa, Velocity = 300 m/s, Internal energy = 2000 kJ/kg, Specific volume = 0.4 m3/kg.
At exit : Pressure = 200 kPa, Velocity = 300 m/s, Internal energy = 1600 kJ/kg, Specific volume = 1.0 m3/kg.
The system is considered to be adiabatic. Neglect the change in potential energy of the system. What will be the power (developed/consumed) by the system?
1
2.2 MW is developed by the system
2
2.2 MW is consumed by the system
3
2.2 kW is consumed by the system
4
2.2 KW is developed by the system