A particle of mass m is moving in a horizontal circle of radius r under the action of centripetal force expressed as \(-\frac{C}{r^2}\), where C is constant. The total energy of the particle is:

1
\(\frac{C}{2r}\)
2
\(-\frac{C}{2r}\)
3
\(\frac{2C}{r}\)
4
\(\frac{C}{r}\)

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation