Consider the following equations of two alternating sinusoidal voltages having the same angular frequency ω
e1 = 2 sin (ωt)
\({e_2} = 6\sqrt 2 \sin \left( {\omega t + \frac{\pi }{4}} \right)\;\)
The equation for the resultant voltage is given by:1
\({e_r} = 8.71\sin \left\{ {\omega t + {{\tan }^{ - 1}}\frac{1}{{3\sqrt 2 }}} \right\}V\)
2
\({e_r} = 10\sin \left\{ {\omega t + {{\tan }^{ - 1}}\frac{3}{4}} \right\}V\)
3
\({e_r} = 8.71\sin \left\{ {\omega t + {{\tan }^{ - 1}}\left( {3\sqrt 2 } \right)} \right\}V\)
4
\({e_r} = 10\sin \left\{ {\omega t + {{\tan }^{ - 1}}\frac{4}{3}} \right\}V\)