Two bars of same length and different materials are subjected to same tensile force. The first bar is of uniform diameter D and the other bar has diameter D/2 in middle one-fourth part. Ratio of strain energy is, if \(\frac{{{E_1}}}{{{E_2}}} = \frac{4}{7}\)

1
1
2
\(\frac{4}{7}\)
3
\(\frac{7}{4}\)
4
\(\frac{7}{2}\)

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