Let ϕ be the phase angle between the line current and line voltage, and α be the load angle. The per phase mechanical power developed by a synchronous motor is:

1
\(\frac{{{E_b}V}}{{{X_S}}}\sin \phi \)
2
\(\frac{{{E_b}V}}{{{X_S}}}\cos \alpha \)
3
\(\frac{{{E_b}V}}{{{X_s}}}\cos \phi \)
4
\(\frac{{{E_b}V}}{{{X_S}}}\sin \alpha \)

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