If \({\left( {{\rm{x}} + {\rm{}}\frac{1}{{\rm{x}}}} \right)^2} = 16\), then, find the value of \(\frac{{{{\rm{x}}^2} + 1}}{{{{\rm{x}}^2} - 1}}\)

1
2
2
4
3
2/√3
4
\(3\sqrt 2\)

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