Two resistances 1Ω and 4Ω are connected in the left and right gaps of a Wheatstone's meter bridge. The balancing length 'l' is noted. Now the resistances are interchanged in the two gaps. The new balancing length 'L' is noted Then 

1
\(\frac{l}{L} = \frac{1}{4}\)
2
l = L
3
L = l = 69 cm
4
l - L = 60 cm

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