If (13x + 9)3 + (4 - x)3 - 8(3x - 5)3 = 6(13x + 9)(x - 4)(3x - 5), then what is the value of \(\sqrt{x^2-10}\) ?

1
\(\frac{13}{6}\)
2
\(\frac{19}{4}\)
3
\(\frac{17}{6}\)
4
\(\frac{9}{4}\)

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