The current enters to the positive terminal of a device is i(t) = e-4t amps, and the voltage across the device is v(t) = 3 d(i)/dt volt. The amount of energy absorbed (in Joule) in between t = 0 and t = 2 seconds is in the range of
(e-16 = 1.125 × 10-7 )
1
- 5.89 to - 5.90
2
- 5.99 to - 6.00
3
- 4.711 to - 4.713
4
-1.49 to -1.51