engineering recuitment GATE EE 2023-24 Test Series Electromagnetic Theory Electrostatics Electrostatic Field
Electric Potential is given by \(V = x^2y^2\), Then the magnitude of the electric field at x = 2 m, y =1 m is?
1
\(\sqrt{40}\) v/m
2
\(\sqrt{80}\) v/m
3
\(\sqrt{32}\) v/m
4
\(\sqrt{16}\) v/m