The inverse fourier transform of \(\frac{d}{{d\omega }}\left( {\frac{{4\sin 4\omega \sin 2\omega }}{\omega }} \right)\) is:
1
\(t\left[ {rect\left( {\frac{{t - 2}}{8}} \right)} \right] + t\left[ {rect\;\left( {\frac{{t + 2}}{8}} \right)} \right]\)
2
\(t\left[ {rect\left( {\frac{{t - 2}}{8}} \right)} \right] - t\left[ {rect\;\left( {\frac{{t + 2}}{8}} \right)} \right]\)
3
\(2t\left[ {rect\left( {t + 2} \right)} \right] + t\left[ {rect\;\left( {\frac{{t - 2}}{8}} \right)} \right]\)
4
None of the above