If \(A = \left[ {\begin{array}{*{20}{c}} 1&1&3\\ 5&2&6\\ { - 2}&{ - 1}&{ - 3} \end{array}} \right]\),
then the value of A14 + 3A – 2I is
1
0
2
\(\left[ {\begin{array}{*{20}{c}} 1&0&0\\ 0&1&0\\ 0&0&1 \end{array}} \right]\)
3
\(\left[ {\begin{array}{*{20}{c}} 3&3&9\\ {15}&6&{18}\\ { - 6}&{ - 3}&{ - 9} \end{array}} \right]\)
4
\(\left[ {\begin{array}{*{20}{c}} 1&3&9\\ {15}&4&{18}\\ { - 6}&{ - 3}&{ - 11} \end{array}} \right]\)