The turns ratio in the Y-\(\triangle \) connection is x ∶ 5. If the voltage and current at the primary side are V and I then what will be the line voltage and line current for the secondary side respectively.

1
\(\frac{5V}{\sqrt3x}\) , \(\frac{\sqrt{3}{\;I}x}{5}\)
2
\(\frac{\sqrt3x}{5V}, \frac{5I}{\sqrt3x}\)
3
\(\frac{5V}{3x}, \frac{3I}{5}\)
4
\(\frac{3x}{5V}, \frac{5}{3I}\)

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