If \(F(s) = L[f(t)] = \frac{(2s+1)}{s^2 + 4s + 7}\) then the initial and final values of f(t) are respectively.
1
0, 2
2
2, 0
3
0, 2/7
4
2/7, 0
If \(F(s) = L[f(t)] = \frac{(2s+1)}{s^2 + 4s + 7}\) then the initial and final values of f(t) are respectively.