In ΔABC, ∠C = 90°, Point P and Q are on the sides AC and BC, respectively, such that AP : PC = BQ : QC = 1 : 2 then, \(\frac{AQ^2+BP^2}{AB^2}\) is equal to:

1
4/9
2
8/3
3
4/3
4
13/9

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation