ABC is an isosceles right angle triangle. Angle ABC = 90 degree and AB = 12 cm. What is the ratio of the radius of the circle inscribed in it to the radius of the circle circumscribing triangle ABC ?

1
6 − \(\sqrt{2}\) ∶ 3\(\sqrt{2}\)
2
2 − \(\sqrt{2}\) ∶ \(\sqrt{2}\)
3
6 − 3\(\sqrt{2}\) ∶ 1\(\sqrt{2}\)
4
6 − 3\(\sqrt{2}\) ∶ 6\(\sqrt{2}\)

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