If the Wheatstone's bridge with four resistors R1, R2, R3, R4 is balanced then the correct expression is

1
\(\frac{\text{R}_2}{\text{R}_1} = \frac{\text{R}_4}{\text{R}_3}\)
2
\(\frac{\text{R}_2}{\text{R}_3} = \frac{\text{R}_1}{\text{R}_4}\)
3
R1R2 = R3R4
4
R1 + R2 = R3 + R4

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