Maximum velocity condition in a flow-through circular channel section is:

1

H = 0.81d; Area of flow = R2/2(θ - sin 2θ)

2

H = 0.81d; Area of flow = R2/2(2 - sin 2θ)

3

H = 0.81d; Area of flow = R2/2(2θ - sin 2θ)

4

H = 0.81D; Area of flow = R2/2(2θ - sin θ)

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