Consider the voltage and current expressions across a load as given below
v = -100 cos (314 t + 15°)
i = 50 sin (314 t - 45°)
Then the power factor of load is:
1
0.5
2
0.866
3
1
4
0
Consider the voltage and current expressions across a load as given below
v = -100 cos (314 t + 15°)
i = 50 sin (314 t - 45°)
Then the power factor of load is: