Assuming that the Op-amp in the circuit shown is ideal, Vo is given by

1
\(\frac{5}{2}{V_1} - 3{V_2}\)
2
\(2{V_1} - \frac{5}{2}{V_2}\)
3
\(- \frac{3}{2}{V_1} + \frac{7}{2}{V_2}\)
4
\(- 3{V_1} + \frac{{11}}{2}{V_2}\)

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