The Z transform of signal x[n] is X(z). If \(X\left( z \right) = \frac{{4z + 5}}{{\left( {z - 2} \right)\left( {z + 5} \right)}}\) and x(-1) = 1, what will be the value of x[n] initially?

1
-1/2
2
1/2
3
-3/2
4
None of the above

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