An FM signal is given as;

\(S(t) = 20\cos\left ( 2\pi f_{c}t + 1000\int_{-\infty}^{t}m(\lambda)d \lambda \right )\)

Where m(t) is shown in the figure given below.

It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal.  

1
fi =998.407 MHz , δf = 5000\π Hz
2
fi =99.8407 kHz , δf = 5\π kHz
3
fi =0.998407 MHz , δf = 5\π kHz
4
fi =998.407 kHz , δf = 50\π kHz

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation