If the following integral is evaluated using Cauchy’s Integral formula

\(\underset{\left| z \right|=1}{\overset{{}}{\mathop \oint }}\,\frac{{{e}^{kz}}}{z}dz\) where k is a real constant.

Then the value of integral

\(\underset{0}{\overset{2\pi }{\mathop \oint }}\,{{e}^{k\cos \theta }}\sin \left( k\sin \theta \right)d\theta =\)