The solution of the differential equation 2x2y'' + 3xy' – 15y = 0, y(1) = 1, y'(1) = 2 is

1
\(y = \frac{{10}}{{11}}{x^{5/2}} + \frac{1}{{11}}{x^{ - 3}}\)
2
\(y = \frac{{12}}{{11}}{x^{ - \frac{5}{2}}} - \frac{1}{{11}}{x^3}\)
3
\(y = \frac{{12}}{{11}}{x^{\frac{5}{2}}} - \frac{1}{{11}}{x^{ - 3}}\)
4
\(y = \frac{{10}}{{11}}{x^{ - 5/2}} + \frac{1}{{11}}{x^3}\)

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