engineering recuitment GATE ECE 2023-24 Test Series Engineering Mathematics Calculus Mean Value Theorem
If \(f'\left( x \right) = \frac{1}{{5 - {x^2}}}\) and f (0) = 1, Assume f (x) is continuous in [0, 1] and differentiable in the interval (0, 1). Lagrange mean value theorem is applicable
1
Lower bound of f (1) is \(\frac{6}{5}\)
2
Upper bound of f (1) is \(- \frac{6}{5}\)
3
Lower bound of f (1) is \(- \frac{5}{4}\)
4
Upper bound of f (1) is \(\frac{5}{4}\)