Where '*' represents the convolution operation

The possible value(s) of x1(t) and x2(t) are:

1
x1(t) = u(t-1) – u(t-2) and x2(t) = u(t) – u(t-2)
2
x1(t) = u(t-1) – u(t-2) and x2(t) = 0.5u(t) – 0.5u(t-2)
3
x1(t) = u(2-t) u(t-1) and x2(t) = u(2-t) u(t)
4
x1(t) = u(t-1) – u(t-2) and x2(t) = u(2-t) u(t)

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