A block of mass M is released from point P on a rough inclined plane with an inclination angle θ, shown in the figure below. The coefficient of friction is μ. If μ < tan θ, then the time taken by the block to reach another point Q on the inclined plane, where PQ = S, is

1
\(\sqrt {\frac{{2s}}{{g\cos \theta \left( {\tan \theta - \mu } \right)}}} \)
2
\(\sqrt {\frac{{2s}}{{g\cos \theta \left( {\tan \theta + \mu } \right)}}} \)
3
\(\sqrt {\frac{{2s}}{{g\sin \theta \left( {\tan \theta - \mu } \right)}}} \)
4
\(\sqrt {\frac{{2s}}{{g\sin \theta \left( {\tan \theta + \mu } \right)}}} \)

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation