Β With initial values y(0) = π¦′(0) = 1, the solution of the differential equation\(\frac{{{d^2}y}}{{d{x^2}}} + 4\frac{{dy}}{{dx}} + 4y = 0\)Β at x =1 isΒ Β _______
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Β With initial values y(0) = π¦′(0) = 1, the solution of the differential equation\(\frac{{{d^2}y}}{{d{x^2}}} + 4\frac{{dy}}{{dx}} + 4y = 0\)Β at x =1 isΒ Β _______
Enter numerical value using the virtual keypad. Round off where necessary.