The velocity distribution V (y) in a wide channel is given by \(v\left( y \right) = 5.75\;\sqrt {g{y_0}{S_0}} \log \left( {\frac{{30y}}{k}} \right)\) in which y is the distance from the bottom of the flow and y0 is the depth of flow, S0 = 0.5 % is the bed slope of the channel, k is the roughness height at the bed. The depth of flow is 2.5 m and the characteristics roughness is 1 cm. If the critical shear stress required to move the bed material is 1 N/m2. ( μ = 0.001 Pa-sec ) (Assume log = log e (natural log))
1
Channel is unstable and Shear stress at 1 cm above the bottom of a channel is 0.201 N/cm2
2
Channel is in stable condition and Shear stress at 1 cm above the bottom of a channel is 0.201 N/m2
3
Channel is in stable condition and Shear stress at 1 cm above the bottom of a channel is 2.01 N/m2
4
Channel is unstable and Shear stress at 1 cm above the bottom of a channel is 2.01 N/cm2