Given f(t) = 3e-4tu(t). Its Fourier transform F(ω) at ω = 4 is

1
\(\frac{1}{{1 + j}}\)
2
\(\frac{{\frac{3}{4}}}{{1 + j}}\)
3
\(\frac{1}{{1 + \frac{4}{3}j}}\)
4
\(\frac{{\frac{4}{3}}}{{1 + \frac{4}{3}j}}\)

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